Optimal. Leaf size=161 \[ -\frac {\sqrt {a^2+2 a b x+b^2 x^2} (a+2 b x) \sqrt {c+d x^2}}{2 x^2 (a+b x)}+\frac {b \sqrt {d} \sqrt {a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{a+b x}-\frac {a d \sqrt {a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac {\sqrt {c+d x^2}}{\sqrt {c}}\right )}{2 \sqrt {c} (a+b x)} \]
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Rubi [A] time = 0.12, antiderivative size = 161, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 8, integrand size = 35, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.229, Rules used = {1001, 811, 844, 217, 206, 266, 63, 208} \begin {gather*} -\frac {\sqrt {a^2+2 a b x+b^2 x^2} (a+2 b x) \sqrt {c+d x^2}}{2 x^2 (a+b x)}+\frac {b \sqrt {d} \sqrt {a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{a+b x}-\frac {a d \sqrt {a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac {\sqrt {c+d x^2}}{\sqrt {c}}\right )}{2 \sqrt {c} (a+b x)} \end {gather*}
Antiderivative was successfully verified.
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Rule 63
Rule 206
Rule 208
Rule 217
Rule 266
Rule 811
Rule 844
Rule 1001
Rubi steps
\begin {align*} \int \frac {\sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{x^3} \, dx &=\frac {\sqrt {a^2+2 a b x+b^2 x^2} \int \frac {\left (2 a b+2 b^2 x\right ) \sqrt {c+d x^2}}{x^3} \, dx}{2 a b+2 b^2 x}\\ &=-\frac {(a+2 b x) \sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{2 x^2 (a+b x)}-\frac {\sqrt {a^2+2 a b x+b^2 x^2} \int \frac {-4 a b c d-8 b^2 c d x}{x \sqrt {c+d x^2}} \, dx}{4 c \left (2 a b+2 b^2 x\right )}\\ &=-\frac {(a+2 b x) \sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{2 x^2 (a+b x)}+\frac {\left (a b d \sqrt {a^2+2 a b x+b^2 x^2}\right ) \int \frac {1}{x \sqrt {c+d x^2}} \, dx}{2 a b+2 b^2 x}+\frac {\left (2 b^2 d \sqrt {a^2+2 a b x+b^2 x^2}\right ) \int \frac {1}{\sqrt {c+d x^2}} \, dx}{2 a b+2 b^2 x}\\ &=-\frac {(a+2 b x) \sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{2 x^2 (a+b x)}+\frac {\left (a b d \sqrt {a^2+2 a b x+b^2 x^2}\right ) \operatorname {Subst}\left (\int \frac {1}{x \sqrt {c+d x}} \, dx,x,x^2\right )}{2 \left (2 a b+2 b^2 x\right )}+\frac {\left (2 b^2 d \sqrt {a^2+2 a b x+b^2 x^2}\right ) \operatorname {Subst}\left (\int \frac {1}{1-d x^2} \, dx,x,\frac {x}{\sqrt {c+d x^2}}\right )}{2 a b+2 b^2 x}\\ &=-\frac {(a+2 b x) \sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{2 x^2 (a+b x)}+\frac {b \sqrt {d} \sqrt {a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{a+b x}+\frac {\left (a b \sqrt {a^2+2 a b x+b^2 x^2}\right ) \operatorname {Subst}\left (\int \frac {1}{-\frac {c}{d}+\frac {x^2}{d}} \, dx,x,\sqrt {c+d x^2}\right )}{2 a b+2 b^2 x}\\ &=-\frac {(a+2 b x) \sqrt {a^2+2 a b x+b^2 x^2} \sqrt {c+d x^2}}{2 x^2 (a+b x)}+\frac {b \sqrt {d} \sqrt {a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{a+b x}-\frac {a d \sqrt {a^2+2 a b x+b^2 x^2} \tanh ^{-1}\left (\frac {\sqrt {c+d x^2}}{\sqrt {c}}\right )}{2 \sqrt {c} (a+b x)}\\ \end {align*}
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Mathematica [A] time = 0.12, size = 126, normalized size = 0.78 \begin {gather*} -\frac {\sqrt {(a+b x)^2} \sqrt {c+d x^2} \left (c (a+2 b x) \sqrt {\frac {d x^2}{c}+1}+a d x^2 \tanh ^{-1}\left (\sqrt {\frac {d x^2}{c}+1}\right )-2 b \sqrt {c} \sqrt {d} x^2 \sinh ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c}}\right )\right )}{2 c x^2 (a+b x) \sqrt {\frac {d x^2}{c}+1}} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.41, size = 115, normalized size = 0.71 \begin {gather*} \frac {\sqrt {(a+b x)^2} \left (\frac {(-a-2 b x) \sqrt {c+d x^2}}{2 x^2}+\frac {a d \tanh ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c}}-\frac {\sqrt {c+d x^2}}{\sqrt {c}}\right )}{\sqrt {c}}-b \sqrt {d} \log \left (\sqrt {c+d x^2}-\sqrt {d} x\right )\right )}{a+b x} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 0.44, size = 377, normalized size = 2.34 \begin {gather*} \left [\frac {2 \, b c \sqrt {d} x^{2} \log \left (-2 \, d x^{2} - 2 \, \sqrt {d x^{2} + c} \sqrt {d} x - c\right ) + a \sqrt {c} d x^{2} \log \left (-\frac {d x^{2} - 2 \, \sqrt {d x^{2} + c} \sqrt {c} + 2 \, c}{x^{2}}\right ) - 2 \, {\left (2 \, b c x + a c\right )} \sqrt {d x^{2} + c}}{4 \, c x^{2}}, -\frac {4 \, b c \sqrt {-d} x^{2} \arctan \left (\frac {\sqrt {-d} x}{\sqrt {d x^{2} + c}}\right ) - a \sqrt {c} d x^{2} \log \left (-\frac {d x^{2} - 2 \, \sqrt {d x^{2} + c} \sqrt {c} + 2 \, c}{x^{2}}\right ) + 2 \, {\left (2 \, b c x + a c\right )} \sqrt {d x^{2} + c}}{4 \, c x^{2}}, \frac {a \sqrt {-c} d x^{2} \arctan \left (\frac {\sqrt {-c}}{\sqrt {d x^{2} + c}}\right ) + b c \sqrt {d} x^{2} \log \left (-2 \, d x^{2} - 2 \, \sqrt {d x^{2} + c} \sqrt {d} x - c\right ) - {\left (2 \, b c x + a c\right )} \sqrt {d x^{2} + c}}{2 \, c x^{2}}, -\frac {2 \, b c \sqrt {-d} x^{2} \arctan \left (\frac {\sqrt {-d} x}{\sqrt {d x^{2} + c}}\right ) - a \sqrt {-c} d x^{2} \arctan \left (\frac {\sqrt {-c}}{\sqrt {d x^{2} + c}}\right ) + {\left (2 \, b c x + a c\right )} \sqrt {d x^{2} + c}}{2 \, c x^{2}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.28, size = 199, normalized size = 1.24 \begin {gather*} \frac {a d \arctan \left (-\frac {\sqrt {d} x - \sqrt {d x^{2} + c}}{\sqrt {-c}}\right ) \mathrm {sgn}\left (b x + a\right )}{\sqrt {-c}} - b \sqrt {d} \log \left ({\left | -\sqrt {d} x + \sqrt {d x^{2} + c} \right |}\right ) \mathrm {sgn}\left (b x + a\right ) + \frac {{\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{3} a d \mathrm {sgn}\left (b x + a\right ) + 2 \, {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2} b c \sqrt {d} \mathrm {sgn}\left (b x + a\right ) + {\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )} a c d \mathrm {sgn}\left (b x + a\right ) - 2 \, b c^{2} \sqrt {d} \mathrm {sgn}\left (b x + a\right )}{{\left ({\left (\sqrt {d} x - \sqrt {d x^{2} + c}\right )}^{2} - c\right )}^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.02, size = 141, normalized size = 0.88 \begin {gather*} -\frac {\left (a \sqrt {c}\, d^{\frac {3}{2}} x^{2} \ln \left (\frac {2 c +2 \sqrt {d \,x^{2}+c}\, \sqrt {c}}{x}\right )-2 b c d \,x^{2} \ln \left (\sqrt {d}\, x +\sqrt {d \,x^{2}+c}\right )-2 \sqrt {d \,x^{2}+c}\, b \,d^{\frac {3}{2}} x^{3}-\sqrt {d \,x^{2}+c}\, a \,d^{\frac {3}{2}} x^{2}+2 \left (d \,x^{2}+c \right )^{\frac {3}{2}} b \sqrt {d}\, x +\left (d \,x^{2}+c \right )^{\frac {3}{2}} a \sqrt {d}\right ) \mathrm {csgn}\left (b x +a \right )}{2 c \sqrt {d}\, x^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sqrt {d x^{2} + c} \sqrt {{\left (b x + a\right )}^{2}}}{x^{3}}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {\sqrt {{\left (a+b\,x\right )}^2}\,\sqrt {d\,x^2+c}}{x^3} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sqrt {c + d x^{2}} \sqrt {\left (a + b x\right )^{2}}}{x^{3}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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